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if a vector potential A=(x^2+y^2-z^2)j at position (x,y,z),what is the magnetic field at(1,1,1)?

on 2012-12-02 17:31:59   by joy   on Computer Science & Engineering  1 answers

neha

on 2012-12-02 10:30:00  

B=gradXA-from the vector potential we know this.. thus,B=cross product of grad and A(x^2+y^2-z^2) at the ultimate answer put x=1,y=1,z=1....